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A body of mass' $\mathrm{m}$ ' and radius of gyration ' $\mathrm{K}$ ' has an angular momentum ' $L$ '. Then its angular velocity is
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The correct answer is:
$\frac{\mathrm{L}}{\mathrm{mK}^2}$
$\begin{aligned} & \mathrm{I}=\mathrm{mK}^2 \text { and } \mathrm{L}=\mathrm{I} \omega=\mathrm{mK}^2 \omega \\ & \therefore \omega=\frac{\mathrm{L}}{\mathrm{mK}^2}\end{aligned}$
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