A body of mass M at rest explodes into three pieces, two of which of mass M 4 each are thrown off in mutually perpendicular directions with speeds of 3 m s - 1 and 4 m s - 1 respectively. Then the third piece will be thrown off with a speed of

Question

A body of mass M at rest explodes into three pieces, two of which of mass M 4 each are thrown off in mutually perpendicular directions with speeds of 3 m s - 1 and 4 m s - 1 respectively. Then the third piece will be thrown off with a speed of, 1 . 5 m s - 1, 2 . 0 m s - 1, 2 . 5 m s - 1, 3 . 0 m s - 1

MARKS App · Accepted Answer

As there is no external force, hence p → = p → 1 + p → 2 + p → 3 = constant ⇒ p → 3 = p → 1 + p → 2 = m 4 3 2 + 4 2 = 5 m 4 [since v 1 and v 2 are mutually perpendicular] ∴ p 3 = m 2 v 3 = 5 m 4 ⇒ v 3 = 5 2 = 2 . 5 m s - 1

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