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A body of mass $M$ hits normally a rigid wall with velocity $y$ and bounces back with the same velocity. The impulse experienced by the body is
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Verified Answer
The correct answer is:
$2 \mathrm{Mv}$
Impulse
$\begin{aligned}
|J| & =|\Delta p| \\
& =M v-(-Mv) \\
& =2 Mv
\end{aligned}$
$\begin{aligned}
|J| & =|\Delta p| \\
& =M v-(-Mv) \\
& =2 Mv
\end{aligned}$
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