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A body of mass $m$ is suspended to an ideal spring of force constant $k$. The expected change in the position of the body due to an additional force $F$ acting vertically downwards is
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Verified Answer
The correct answer is:
$\frac{2 F}{k}$
Let the change in position of the body due to additional force is $x$.
So,
$\begin{aligned}
& F=\frac{1}{2} k x \\
& x=\frac{2 F}{k}
\end{aligned}$
$\therefore \quad x=\frac{2 F}{k}$
So,
$\begin{aligned}
& F=\frac{1}{2} k x \\
& x=\frac{2 F}{k}
\end{aligned}$
$\therefore \quad x=\frac{2 F}{k}$
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