Search any question & find its solution
Question:
Answered & Verified by Expert
A body of mass $m$ is thrown vertically upward with speed $\sqrt{3} v_e$, where $v_e$ is the escape velocity of a body from earth surface. The final velocity of the body is
Options:
Solution:
2449 Upvotes
Verified Answer
The correct answer is:
$\sqrt{2} \mathrm{v}_{\mathrm{e}}$
$-\frac{\mathrm{GMm}}{\mathrm{R}}+\frac{1}{2} \mathrm{~m}\left(\sqrt{3} \mathrm{v}_{\mathrm{e}}\right)^2=0+\frac{1}{2} \mathrm{mv}^2, \quad \mathrm{v}=\sqrt{2} \mathrm{v}_{\mathrm{e}}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.