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A body of mass $M$ moving with velocity $V$ explodes into two equal parts. If one comes to rest and the other body moves with velocity $v$, what would be the value of $v$ ?
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The correct answer is:
$2 \mathrm{~V}$.
Before explosion, the total momentum of the system $=M V$
After explosion, the total momentum of the system
$$
=\frac{M}{2} \times 0+\frac{M}{2} \times v=\frac{M v}{2}
$$
From the principal of momentum conservation,
$$
\begin{aligned}
& M V=\frac{M v}{2} \\
\Rightarrow \quad & v=2 V
\end{aligned}
$$
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