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A body of mass 'M' moving with velocity 'V' explodes into two equal parts. If one
part comes to rest and the other part moves with velocity ' $\mathrm{v}_{0}$ ', what would be the
value of $^{\prime} \mathrm{V}_{0}$ '?
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part comes to rest and the other part moves with velocity ' $\mathrm{v}_{0}$ ', what would be the
value of $^{\prime} \mathrm{V}_{0}$ '?
Solution:
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Verified Answer
The correct answer is:
$2 \mathrm{~V}$
conservation of linear momentum
$\begin{aligned} \text { initial } &=\text { final } \\ \text { MV } &=\frac{m}{2}(0)+\frac{m}{2}(u) \\ M V &=\frac{M}{2} u \\ u &=2 v \end{aligned}$
$\begin{aligned} \text { initial } &=\text { final } \\ \text { MV } &=\frac{m}{2}(0)+\frac{m}{2}(u) \\ M V &=\frac{M}{2} u \\ u &=2 v \end{aligned}$
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