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Question: Answered & Verified by Expert
A body of weight $2 \mathrm{~kg}$ is suspended as shown in the figure. The tension $T_1$ in the horizontal string (in $\mathrm{kg} w t$ ) is

PhysicsLaws of MotionJEE Main
Options:
  • A $2 / \sqrt{3}$
  • B $\sqrt{3} / 2$
  • C $2 \sqrt{3}$
  • D 2
Solution:
2455 Upvotes Verified Answer
The correct answer is: $2 \sqrt{3}$


$\begin{aligned} & T \sin 30=2 \mathrm{~kg} w t \\ & \Rightarrow T=4 \mathrm{~kg} w t \\ & T_1=T \cos 30^{\circ} \\ & =4 \cos 30^{\circ} \\ & =2 \sqrt{3}\end{aligned}$

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