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Question: Answered & Verified by Expert
A body of weight $200 \mathrm{~N}$ is suspended from a tree branch through a chain of mass $10 \mathrm{~kg}$. The branch pulls the chain by a force equal to (if $g=10 \mathrm{~m} / \mathrm{s}^2$ ) :
PhysicsLaws of MotionJEE MainJEE Main 2024 (06 Apr Shift 2)
Options:
  • A $100 \mathrm{~N}$
  • B $200 \mathrm{~N}$
  • C $300 \mathrm{~N}$
  • D $150 \mathrm{~N}$
Solution:
2982 Upvotes Verified Answer
The correct answer is: $300 \mathrm{~N}$

Chain block system is in equilibrium so
$\mathrm{T}=200+100=300 \mathrm{~N} \text {. }$

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