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A body of weight $64 \mathrm{~N}$ is pushed with just enough force to start it moving across a horizontal floor and the same force continues to act afterwards. If the coefficients of static and dynamic friction are 0.6 and 0.4 respectively, the acceleration of the body is (Acceleration due to gravity $=g$ )
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The correct answer is:
$0.2 \mathrm{~g}$
$w=64 \mathrm{~N}, \mu_i=0.6, \mu_k=0.4$
Acceleration of the body
$\begin{aligned} & =\left(\mu_{,}-\mu_k\right) g \\ & =(0.6-0.4) \times g \\ & =0.2 \mathrm{~g} \mathrm{~m} / \mathrm{s}^2\end{aligned}$
Acceleration of the body
$\begin{aligned} & =\left(\mu_{,}-\mu_k\right) g \\ & =(0.6-0.4) \times g \\ & =0.2 \mathrm{~g} \mathrm{~m} / \mathrm{s}^2\end{aligned}$
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