Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A body travels for $15 \mathrm{sec}$ starting from rest with constant acceleration. If it travels distances $s_1, s_2$ and $s_3$ in the first five seconds, second five seconds and next five seconds respectively the relation between $s_1, s_2$ and $S_3$ is
PhysicsMotion In One DimensionJEE Main
Options:
  • A $S_1=S_2=S_3$
  • B $5 S_1=3 S_2=S_3$
  • C $S_1=\frac{1}{3} S_2=\frac{1}{5} S_3$
  • D $s_1=\frac{1}{5} s_2=\frac{1}{3} s_3$
Solution:
2412 Upvotes Verified Answer
The correct answer is: $S_1=\frac{1}{3} S_2=\frac{1}{5} S_3$
If the body starts from rest and moves with constant acceleration then the ratio of distances in consecutive equal time interval $S_1: S_2: S_3=1: 3: 5$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.