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A bomb is dropped on an enemy post on the ground by an aeroplane flying horizontally with a velocity of $60 \mathrm{kmh}^{-1}$ at a height of $490 \mathrm{~m}$. At the time of dropping the bomb, the horizontal distance of the aeroplane from the enemy post so that the bomb hits the target is
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Verified Answer
The correct answer is:
$\left(\frac{500}{3}\right) m$
Velocity, (u) $=60 \frac{\mathrm{km}}{\mathrm{h}}=\frac{60 \times 1000}{60 \times 60} \frac{\mathrm{m}}{\mathrm{s}}$ Height, (h) = $490 \mathrm{~m}$
$\begin{aligned}
& S=u t \\
& =\sqrt[u]{\frac{2 h}{g}}\left(\because h=u t+\frac{1}{2} g t^2\right) \\
& =\frac{60 \times 1000}{60 \times 60} \times \frac{\sqrt{2 \times 490}}{9.8}=\frac{500}{3} \mathrm{~m}
\end{aligned}$
$\begin{aligned}
& S=u t \\
& =\sqrt[u]{\frac{2 h}{g}}\left(\because h=u t+\frac{1}{2} g t^2\right) \\
& =\frac{60 \times 1000}{60 \times 60} \times \frac{\sqrt{2 \times 490}}{9.8}=\frac{500}{3} \mathrm{~m}
\end{aligned}$
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