A bomb of mass 9 k g explodes into two parts. One part of mass 3 k g moves with a velocity of 16 m s - 1 , then the kinetic energy of the other part is

Question

A bomb of mass 9 k g explodes into two parts. One part of mass 3 k g moves with a velocity of 16 m s - 1 , then the kinetic energy of the other part is, 192 J, 200 J, 300 J, 400 J

MARKS App · Accepted Answer

From momentum conservation principle 0 = 3 16 + 6 v 2 ⇒ v 2 = – 8 m / s K 2 = 1 2 m 2 v 2 2 = 1 2 ( 6 ) ( − 8 ) 2 = 192 J

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