A bomber plane moves horizontally with a speed of 500 m s - 1 and a bomb released from it, strikes the ground in 10 s . The angle at which it strikes the ground will be ( g = 10 m s - 2 )

Question

A bomber plane moves horizontally with a speed of 500 m s - 1 and a bomb released from it, strikes the ground in 10 s . The angle at which it strikes the ground will be ( g = 10 m s - 2 ), t a n - 1 1 5, t a n -1 1 15, tan - 1 ( 1 ), tan - 1 ( 5 )

MARKS App · Accepted Answer

Horizontal velocity remains some v x = 500 ms - 1 vertical velocity v y = 0 + 10 t v y = 100 ms - 1 tan θ = 100 500 θ = tan - 1 1 5

Search any question & find its solution

Looking for more such questions to practice?