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A box contains \( 100 \) bulbs, out of which \( 10 \) are defective. A sample of \( 5 \) bulbs is drawn. The
probability that none is defective is
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probability that none is defective is
Solution:
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Verified Answer
The correct answer is:
\( \left(\frac{9}{10}\right)^{5} \)
Given that, total number of bulbs are 100 .
Defective bulbs are 10 .
So, $p=\frac{10}{100}=0.1, q=0.9, n=5$
Therefore $p(x)={ }^{5} C_{x}(p)^{x}(q)^{5-x}$
$p(0)={ }^{5} C_{0}(0.1)^{0}(0.9)^{5}$
$=\left(\frac{9}{10}\right)^{5}$
Defective bulbs are 10 .
So, $p=\frac{10}{100}=0.1, q=0.9, n=5$
Therefore $p(x)={ }^{5} C_{x}(p)^{x}(q)^{5-x}$
$p(0)={ }^{5} C_{0}(0.1)^{0}(0.9)^{5}$
$=\left(\frac{9}{10}\right)^{5}$
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