A box contains $ 6 $ red marbles numbers from $ 1 $ through $ 6 $ and $ 4 $ white marbles $ 12 $ through $ 15 . $ Find the probability that a marble drawn 'at random' is white and odd numbered.

Question

A box contains $ 6 $ red marbles numbers from $ 1 $ through $ 6 $ and $ 4 $ white marbles $ 12 $ through $ 15 . $ Find the probability that a marble drawn 'at random' is white and odd numbered., $ \frac{1}{7} $, $ \frac{1}{5} $, $ \frac{1}{9} $, $ \frac{1}{6} $

MARKS App · Accepted Answer

Number of red marbles are 6 ( 1 to 6 ) , number of white marbles are 4 ( 12 to 15 ) . So, R1, R2, R3, R4, R5, R6, W12, W13, W14, W15 Total number of marbles are 10. We have, white + odd = W13, W15 So, required probability is 10 2 ​ = 5 1 ​

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