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A box of oranges is inspected by examining three randomly selected oranges drawn without replacement. If all the three oranges are good, the box is approved for sale otherwise it is rejected. Find the probability that a box containing 15 oranges out of which 12 are good and 3 are bad ones will be approved for sale.
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$\mathrm{S}=\{12$ good oranges, 3 bad oranges $\}, n(\mathrm{~S})=15$
$$
\mathrm{P}(\text { a box is approved })=\frac{C(12,3)}{C(15,3)}=\frac{12 \times 11 \times 10}{15 \times 14 \times 13}=\frac{44}{91} \text {. }
$$
$$
\mathrm{P}(\text { a box is approved })=\frac{C(12,3)}{C(15,3)}=\frac{12 \times 11 \times 10}{15 \times 14 \times 13}=\frac{44}{91} \text {. }
$$
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