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A boy can throw a stone up to a maximum height of $10 \mathrm{~m}$. The maximum horizontal distance that the boy can throw the same stone up to will be
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$20 \mathrm{~m}$
$20 \mathrm{~m}$
maximum vertical height $=\frac{u^2}{2 g}=10 \mathrm{~m}$
Horizontal range of a projectile $=\frac{u^2 \sin 2 \theta}{\mathrm{g}}$
Range is maximum when $\theta=45^{\circ}$
Maximum horizontal range $=\frac{\mathrm{u}^2}{\mathrm{~g}}$
Hence maximum horizontal distance $=20 \mathrm{~m}$.
Horizontal range of a projectile $=\frac{u^2 \sin 2 \theta}{\mathrm{g}}$
Range is maximum when $\theta=45^{\circ}$
Maximum horizontal range $=\frac{\mathrm{u}^2}{\mathrm{~g}}$
Hence maximum horizontal distance $=20 \mathrm{~m}$.
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