A boy is standing on an open truck. The truck is moving with acceleration 2 m s - 2 on a horizontal road. When the speed of the truck is 10 m s - 1 and reaches to an electric pole, boy projected a ball with velocity 10 m s - 1 in a vertically upward direction relative to himself take g = 10 m s - 2 . Neglect the height of boy and truck. The distance of the ball from the pole where ball land is

Question

A boy is standing on an open truck. The truck is moving with acceleration 2 m s - 2 on a horizontal road. When the speed of the truck is 10 m s - 1 and reaches to an electric pole, boy projected a ball with velocity 10 m s - 1 in a vertically upward direction relative to himself take g = 10 m s - 2 . Neglect the height of boy and truck. The distance of the ball from the pole where ball land is, 20 m, 10 m, 30 m, 40 m

MARKS App · Accepted Answer

Take x-axis along the motion of truck and y-axis vertically upward v → b a l l / b o y = 10 i ^ m s - 1 v → b o y / ground = 10 j ^ m s - 1 v → b a l l / ground = 10 i ^ + 10 j ^ The distance of the ball from pole = u 2 sin ⁡ 2 θ g = 10 2 2 × sin ⁡ 90 ° g = 20 m

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