A boy of mass 50 kg is climbing a vertical pole at a constant speed. If coefficient of friction between his palms and the pole is 0.75 , then the normal reaction between him and the pole is (take g = 10 m / s 2 )

Question

A boy of mass 50 kg is climbing a vertical pole at a constant speed. If coefficient of friction between his palms and the pole is 0.75 , then the normal reaction between him and the pole is (take g = 10 m / s 2 ), 700 N, 625.67 N, 550 N, 666.67 N

MARKS App · Accepted Answer

Let the normal reaction is N . Since, the boy is climbing with constant speed. ∴ F n e t = 0 (on the boy) Free body diagram m g = f r (friction force) m g = μ N ∵ f r = μ N ⇒ N = m g μ = 50 × 10 0.75 = 666.67 N

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