A bullet fired into a fixed target loses half its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

Question

A bullet fired into a fixed target loses half its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?, 1 . 5 cm, 1 . 0 cm, 3 . 0 cm, 2 . 0 cm

MARKS App · Accepted Answer

For first part of penetration, by equation of motion, ( u ⁡ 2 ) 2 = ( u ⁡ ) 2 - 2 f ⁡ ( 3 ) or 3 u ⁡ 2 = 2 4 f ⁡ For latter part of penetration, 0 = ( u ⁡ 2 ) 2 - 2 f ⁡ x or u ⁡ 2 = 8 f ⁡ x Therefore, 3 × ( 8 f ⁡ x ) = 2 4 f ⁡ or x = 1 cm

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