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Question: Answered & Verified by Expert
A bullet of 4 g mass is fired from a gun of mass 4 kg. If the bullet moves with the muzzle speed of 50 ms1, the impulse imparted to the gun and velocity of recoil of gun are 
PhysicsLaws of MotionJEE MainJEE Main 2021 (22 Jul Shift 1)
Options:
  • A 0.4 kg m s-1, 0.1 m s-1
  • B 0.2 kg m s-1, 0.05 m s-1
  • C 0.2 kg m s-1, 0.1 m s-1
  • D 0.4 kg m s-1, 0.05 m s-1
Solution:
1083 Upvotes Verified Answer
The correct answer is: 0.2 kg m s-1, 0.05 m s-1

By momentum conservation,
4×10-3(50-v)-4v=0
v=4×10-3×504+4×10-30.05 m s-1
Impulse  J=mv=4×.05=0.2 kg m s-1

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