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Question: Answered & Verified by Expert
A bullet of mass $\mathrm{m}$ moving with velocity 'v' is fired into a wooden block of mass 'M'. If the bullet remains embedded in the block, the final velocity of the system is
PhysicsCenter of Mass Momentum and CollisionMHT CETMHT CET 2020 (16 Oct Shift 1)
Options:
  • A $\frac{V}{m(M+m)}$
  • B $\frac{m+M}{m}$
  • C $\frac{\mathrm{M}+\mathrm{m}}{\mathrm{mV}}$
  • D $\frac{\mathrm{mV}}{\mathrm{m}+\mathrm{M}}$
Solution:
2770 Upvotes Verified Answer
The correct answer is: $\frac{\mathrm{mV}}{\mathrm{m}+\mathrm{M}}$
Since there is no extra force other than the action and reaction force so the linear momentum should be conserved.
Suppose the system moves with velocity V then momentum before collision is mv and that after collision will be $(M+$ $\mathrm{m}) \mathrm{V}$
Equating both we get $m v=(M+m) V$ or $V=\frac{m}{m+M}^{v}$

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