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A bullet of mass $\mathrm{m}$ moving with velocity 'v' is fired into a wooden block of mass 'M'. If the bullet remains embedded in the block, the final velocity of the system is
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The correct answer is:
$\frac{\mathrm{mV}}{\mathrm{m}+\mathrm{M}}$
Since there is no extra force other than the action and reaction force so the linear momentum should be conserved.
Suppose the system moves with velocity V then momentum before collision is mv and that after collision will be $(M+$ $\mathrm{m}) \mathrm{V}$
Equating both we get $m v=(M+m) V$ or $V=\frac{m}{m+M}^{v}$
Suppose the system moves with velocity V then momentum before collision is mv and that after collision will be $(M+$ $\mathrm{m}) \mathrm{V}$
Equating both we get $m v=(M+m) V$ or $V=\frac{m}{m+M}^{v}$
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