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Question: Answered & Verified by Expert
A calorimeter contains 70.2 g of water at 15.3 °C. If 143.7 g of water at 36.5 °C is mixed with it, the common temperature becomes 28.7 °C. The water equivalent of the calorimeter is
PhysicsThermal Properties of MatterNEET
Options:
  • A 15.6 g
  • B 9.4 g
  • C 6.3 g
  • D 13.4 g
Solution:
1705 Upvotes Verified Answer
The correct answer is: 13.4 g
Let m be the water equivalent of the calorimeter. Then,

70.2+m28.7-15.3=143.7 36.5-28.7

m=13.4 g

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