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Question: Answered & Verified by Expert
A capacitor C is fully charged with voltage V0. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance C2. The energy loss in the process after the charge is distributed between the two capacitors is :
PhysicsCapacitanceJEE Main
Options:
  • A 12CV02
  • B 13CV02
  • C 14CV02
  • D 16CV02
Solution:
2765 Upvotes Verified Answer
The correct answer is: 16CV02

Heat Loss is given by, 

H=C1C22C1+C2V1-V22

V1 is initial voltage of capacitor C=V0

V2 is the initial voltage of capacitor C2=0

=c×c22c+c2V0-02=C6V02

H=16C0V02

 

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