A capacitor is charged and then made to discharge through a resistance. The time constant is $ \tau $. In what time will the potential difference across the capacitor decrease by $ 10 \% ? $

Question

A capacitor is charged and then made to discharge through a resistance. The time constant is $ \tau $. In what time will the potential difference across the capacitor decrease by $ 10 \% ? $, $ \tau \ln 0.1 $, $ \tau \ln 0.9 $, $ \tau \ln \frac{10}{9} $, $ \tau \ln \frac{11}{10} $

MARKS App · Accepted Answer

As we know the discharging of capacitor is given by q = q 0 e - t τ Also V = V o e − t τ Here V = 9 10 V o putting the values 9 10 V o = V o e − t τ ℓ n ( 9 10 ) = − t τ ℓ n ( 10 9 ) = t τ t = τ ℓ n ( 10 9 )

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