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Question: Answered & Verified by Expert
A capacitor of capacitance 900 µF is charged by a 100 V battery. The capacitor is disconnected from the battery and connected to another uncharged identical capacitor such that one plate of uncharged capacitor connected to positive plate and another plate of uncharged capacitor connected to negative plate of the charged capacitor. The loss of energy in this process is measured as x×10-2 J.  The value of x is ______.
PhysicsCapacitanceJEE MainJEE Main 2023 (30 Jan Shift 1)
Solution:
2751 Upvotes Verified Answer
The correct answer is: 225

When a charged capacitor is connected to an uncharged capacitor, then there is loss of energy in the form of heat as charges flow from higher potential to lower potential.

So, heat H=12C1C2C1+C2 V1-V22 

As the other capacitor is identical therefore charge is equally divided.

=12C22C(100-0)2

=12900×10-62×104=94 Joule

=2.25 Joule.

Hence, the value of x=225.

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