Search any question & find its solution
Question:
Answered & Verified by Expert
A capacitor of capacity $C_1$ is charged to the potential of $V_0$. On disconnecting with the battery, it is connected with a capacitor of capacity $C_2$ as shown in the adjoining figure. The ratio of energies before and after the connection of switch $S$ will be
Options:
Solution:
2229 Upvotes
Verified Answer
The correct answer is:
$\left(C_1+C_2\right) / C_1$
$\begin{aligned} & \text { Energy }(C)=\frac{q^2}{2 C} . \text { q remains same so } U \propto \frac{1}{C} \\ & \Rightarrow \frac{U_{\text {Betore }}}{U_{\text {nner }}}=\frac{C_1+C_2}{C_1}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.