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A capillary tube $(\mathrm{A})$ is dropped in water. Another identical tube $(\mathrm{B})$ is dipped in a soap water solution. Which of the following shows the relative nature of the liquid columns in the two tubes?
Options:
- A
- B
- C
- D
Solution:
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Verified Answer
The correct answer is:
Capillary rise $\mathrm{h}=\frac{2 \mathrm{~T} \cos \theta}{\rho \mathrm{gr}}$. As soap solution has lower $\mathrm{T}, \mathrm{h}$ will be low.
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