A capillary tube of the radius 0 .5 mm is immersed in a beaker of mercury. The level inside the tube is 0 .8 cm below the level in beaker and angle of contact is 120 ° . What is the surface tension of mercury, if the mass density of mercury is ρ = 13.6 × 10 3 kg m - 3 and acceleration due to gravity is g = 10 m s - 2 ?

Question

A capillary tube of the radius 0 .5 mm is immersed in a beaker of mercury. The level inside the tube is 0 .8 cm below the level in beaker and angle of contact is 120 ° . What is the surface tension of mercury, if the mass density of mercury is ρ = 13.6 × 10 3 kg m - 3 and acceleration due to gravity is g = 10 m s - 2 ?, 0 .225 N m - 1, 0 .544 N m - 1, 0 .285 N m - 1, 0 .375 N m - 1

MARKS App · Accepted Answer

Given, The radius of capillary tube = 0 .5 mm = 0 .5 × 10 - 3 m Level inside tube = 0 .8 cm = 0 .8 × 10 - 2 m The angle of contract, θ = 120 o The mass density of mercury, ρ = 13.6 × 10 3 kg m - 2 Acceleration due to gravity, g = 10 m s - 2 h = 2 T cos ⁡ θ r ρ g T = h r ρ g 2 cos ⁡ θ = 0.8 × 10 - 2 × 0.5 × 10 - 3 × 13.6 × 10 3 × 10 2 × cos ⁡ 120 = 0.8 × 10 - 2 × 0.5 × 10 - 3 × 13.6 × 10 3 × 10 2 × 1 2 = 0.8 × 0.5 × 13.6 × 10 - 1 = 0 .544 N m - 1

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