A car is travelling at a velocity 10 km h - 1 on a straight road. The driver of the car throws a parcel with a velocity 10 2 km h - 1 with respect to the car, when the car is passing by a man standing on the side of the road. If the parcel is to reach the man, the direction of throw makes the following angle with the direction of motion of the car

Question

A car is travelling at a velocity 10 km h - 1 on a straight road. The driver of the car throws a parcel with a velocity 10 2 km h - 1 with respect to the car, when the car is passing by a man standing on the side of the road. If the parcel is to reach the man, the direction of throw makes the following angle with the direction of motion of the car, 135 °, 45 °, tan - 1 ⁡ 2, tan - 1 ⁡ 1 2

MARKS App · Accepted Answer

In the vector diagram, O A ¯ and O B ¯ represent the velocity vectors for the car and the parcel, respectively. V → R is the resultant velocity vector. Let θ be the angle between V → c a r and V → P a r c e l . Then, cos ⁡ ( 180 ° - θ ) = V → c a r V → p a r c e l = 10 10 2 = 1 2 180 ° - θ = 45 ° ∴ θ = 135 °

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