Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Open MARKS Web Download App
Search any question & find its solution
Question: Answered & Verified by Expert
A car of mass 1000 kg moves on a circular track of radius 40 m. If the coefficient of friction is 1.28. The maximum velocity with which the car can be moved, is
PhysicsLaws of MotionJIPMERJIPMER 2013
Options:
  • A $22.4 \mathrm{~m} / \mathrm{s}$
  • B $112 \mathrm{~m} / \mathrm{s}$
  • C $\frac{0.64 \times 40}{1000 \times 100} \mathrm{~m} / \mathrm{s}$
  • D $1000 \mathrm{~m} / \mathrm{s}$
Solution:
1799 Upvotes Verified Answer
The correct answer is: $22.4 \mathrm{~m} / \mathrm{s}$
$\begin{aligned} & \text { The maximum velocity } v_{\max }=\sqrt{\mu r g} \\ & =\sqrt{1.28 \times 40 \times 9.8} \\ & =22.4 \mathrm{~m} / \mathrm{s} \\ & \end{aligned}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play