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A car of mass $m$ is moving on a level circular track of radius $R$. If $\mu_s$ represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by
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Verified Answer
The correct answer is:
$\sqrt{\mu_s R g}$
In this condition, centripetal force is equal to static frictional force between road and tyres, so
$$
\begin{aligned}
\mu_s m g & =\frac{m v^2}{R} \\
v_{\max } & =\sqrt{\mu_s R g}
\end{aligned}
$$
$$
\begin{aligned}
\mu_s m g & =\frac{m v^2}{R} \\
v_{\max } & =\sqrt{\mu_s R g}
\end{aligned}
$$
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