Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A Carnot engine, having an efficiency of η=1/10 as a heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at a lower temperature is
PhysicsThermodynamicsNEET
Options:
  • A 99 J
  • B 90 J
  • C 1 J
  • D 100 J
Solution:
2259 Upvotes Verified Answer
The correct answer is: 90 J
Relation between coefficient of performance and efficiency of refrigerator is

     β=1-ηη

 β=1-110110=9

Coefficient of performance, β=Heat absorbed(Q2)Work done (W)

9=Q210

Q2=90 J

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.