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Question: Answered & Verified by Expert
A Carnot engine of efficiency 40 %, takes heat from a source maintained at a temperature of 500 K. It is desired to have an engine of efficiency 60 %. Then, the source temperature for the same sink temperature must be
PhysicsThermodynamicsAP EAMCETAP EAMCET 2019 (21 Apr Shift 2)
Options:
  • A 650 K
  • B 750 K
  • C 550 K
  • D 850 K
Solution:
2224 Upvotes Verified Answer
The correct answer is: 750 K

The formula for the efficiency of Carnot engine Working between temperature limits T1 and T2.T1>T2

η=1-T2T1×100

For η=40 %, T1=500 K

40=1-T2500×100

T2=300 K

For η=60 %,T2=300 K (the source temperature of Carnot
engine for the same sink temp),

  60=1-300T1×100

 T1=750 K

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