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Question: Answered & Verified by Expert
A Carnot engine takes 3×106 caof heat from a reservoir at 627 ℃ and gives it to a sink at 27 ℃. The work done by the engine is
PhysicsThermodynamicsNEET
Options:
  • A 4.2×106 J
  • B 8.4×106 J
  • C 16.8×106 J
  • D Zero
Solution:
2961 Upvotes Verified Answer
The correct answer is: 8.4×106 J
Given, T1=627+273=900K

            Q1=3×106 cal

T2=27+273=300 K

       Q1T1=Q2T2

      Q2=T2T1×Q1

                 =300900×3×106

                 =1×106 cal 

Work done =Q1-Q2

                 =3×106-1×106=2×106cal 

Work done =( 2× 10 6 cal )( 4.2J 1cal )=8.4× 10 6 J

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