A Carnot engine whose low-temperature reservoir is at 350 K has an efficiency of 50 % . It is desired to increase this to 60 % . If the temperature of the low-temperature reservoir remains constant, then the temperature of the high-temperature reservoir must be increased by how many degrees?

Question

A Carnot engine whose low-temperature reservoir is at 350 K has an efficiency of 50 % . It is desired to increase this to 60 % . If the temperature of the low-temperature reservoir remains constant, then the temperature of the high-temperature reservoir must be increased by how many degrees?, 15, 175, 100, 50

MARKS App · Accepted Answer

Efficiency of Carnot engine, η = 1 - T c o l d T h o t × 100 When η = 50 % then 50 100 = 1 - T c o l d T h o t ⇒ 0.5 = 1 - 350 T h o t or T h o t = 700 K When η = 60 % then 60 100 = 1 - T c o l d T h o t ⇒ 0.6 = 1 - 350 T h o t or T h o t = 875 K Hence, the temperature of high reservoir is increased by T ′ h o t - T h o t = 875 K - 700 K = 175 K

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