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A carrier wave of peak voltage $15 \mathrm{~V}$ is used to transmit a message signal. If the modulation index is $60 \%$, then the peak voltage of the modulating signal is
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The correct answer is:
$9 \mathrm{~V}$
The peak voltage for the modulating signal is
$\mathrm{m}=\frac{\mathrm{A}_{\mathrm{m}}}{\mathrm{A}_{\mathrm{C}}} ; \mathrm{A}_{\mathrm{m}}=\mathrm{mA}_{\mathrm{C}}=0.60 \times 15=9 \mathrm{~V}$
$\mathrm{m}=\frac{\mathrm{A}_{\mathrm{m}}}{\mathrm{A}_{\mathrm{C}}} ; \mathrm{A}_{\mathrm{m}}=\mathrm{mA}_{\mathrm{C}}=0.60 \times 15=9 \mathrm{~V}$
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