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Question: Answered & Verified by Expert
A cavity of radius r is made inside a solid sphere. The volume charge density of the remaining sphere is ρ. An electron (charge e, mass m) is released from rest inside the cavity from point P as shown in the figure. The centre of the sphere and centre of the cavity are separated by a distance a. The time after which the electron again touches the sphere is


PhysicsElectrostaticsJEE Main
Options:
  • A 62rε0meρa
  • B 2rε0m6ρa
  • C 6rε0meρa
  • D rε0meρa
Solution:
1068 Upvotes Verified Answer
The correct answer is: 62rε0meρa

E = ρa3ε0 F = eE = eρa3ε0

acceleration = ρea3mε0


  & 



= 12×ρea3mε0×t2 = 2r

t=62rε0meρa

The electron will move opposite to electronic field with constant acceleration along shown horizontal line of length = 2 r

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