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Question: Answered & Verified by Expert
A cell of emf E and internal resistance r is connected in series with an external resistance nr. Then what will be the ratio of the terminal potential difference to emf, if n=9.
PhysicsCurrent ElectricityJEE Main
Solution:
1772 Upvotes Verified Answer
The correct answer is: 0.9

i=En+1r




VT=iR=inr= En+1r× nr

VTE=nn+1=99+1=0.9

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