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A certain gas is taken to the five s t a t e s represented by dots in the graph. The plotted lines are isotherms. Order of the most probable speed \(v_p\) of the molecules at these five states is

PhysicsKinetic Theory of GasesAIIMSAIIMS 2008
Options:
  • A \(v_{p \text { at } 3}>v_{p \text { at } 1}=v_{p \text { at } 2}>v_{p \text { at } 4}=v_p\) at 5
  • B \(v_{p \text { at } 1}>v_{p \text { at } 2}=v_{p \text { at } 3}>v_{p \text { at } 4}=v_p\) at 5
  • C \(v_{p \text { at } 3}>v_{p \text { at } 2}=v_{p \text { at } 4}>v_{p \text { at } 1}=v_{p \text { at } 5}\)
  • D insufficient information to predict the result.
Solution:
1906 Upvotes Verified Answer
The correct answer is: \(v_{p \text { at } 3}>v_{p \text { at } 1}=v_{p \text { at } 2}>v_{p \text { at } 4}=v_p\) at 5
Stages 1 and 2 are at the same temperature. Also stages 4 and 5 are at same temperature. As $V_p$ is more at higher temperature and same at all stages at equal temperature.
$\therefore \quad V_{P_3}>V_{P_1}=V_{P_2}>V_{P_4}=V_{P_5}$.

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