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A certain mass of a gas occupies volume of $250 \mathrm{~mL}$ at $2 \mathrm{~atm}$. Pressure. Calculate the volume of gas if pressure is increased to $2.5 \mathrm{~atm}$ at constant temperature.
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The correct answer is:
200 mL
$\begin{aligned}
& \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\
& 2 \times 250=2.50 \times \mathrm{V}_2(\mathrm{~m} \ell) \\
& \mathrm{V}_2=\frac{2 \times 250}{2.5} \\
& =200 \mathrm{~m} \ell
\end{aligned}$
$\begin{aligned} & \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\ & 2 \times 250=2.50 \times \mathrm{V}_2(\mathrm{~m} \ell) \\ & \mathrm{V}_2=\frac{2 \times 250}{2.5} \\ & =200 \mathrm{~m} \ell\end{aligned}$
& \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\
& 2 \times 250=2.50 \times \mathrm{V}_2(\mathrm{~m} \ell) \\
& \mathrm{V}_2=\frac{2 \times 250}{2.5} \\
& =200 \mathrm{~m} \ell
\end{aligned}$
$\begin{aligned} & \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\ & 2 \times 250=2.50 \times \mathrm{V}_2(\mathrm{~m} \ell) \\ & \mathrm{V}_2=\frac{2 \times 250}{2.5} \\ & =200 \mathrm{~m} \ell\end{aligned}$
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