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Question: Answered & Verified by Expert
A certain metal when irradiated by light r=3.2×1016 Hz emtextts photoelectrons with twice kinetic energy as did photoelectrons when the same metal is irradiated by light r=2.0×1016 Hz. Then v0 of metal is
ChemistryStructure of AtomJEE Main
Options:
  • A 1.2×1014Hz
  • B 8×1015 Hz
  • C 1.2×1016Hz
  • D 4×1012 Hz
Solution:
1394 Upvotes Verified Answer
The correct answer is: 8×1015 Hz
KE1=hv1-hv0

KE2=hv2-hv0

As, KE1=2×KE2

   hv1-hv0=2hv2-hv0

Or, hv0=2hv2-hv1

Or , v0=2v1-v1

=2×2×1016-3.2×1016

=0.8×1016Hz=8×1015 Hz

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