A change of 0 . 04 volts takes place between the base and the emitter when an input signal is connected to the common emitter transistor amplifier. As a result, 20 μA change takes place in the base current and a change of 2 mA takes place in the collector current. The input resistance and AC current gain are

Question

A change of 0 . 04 volts takes place between the base and the emitter when an input signal is connected to the common emitter transistor amplifier. As a result, 20 μA change takes place in the base current and a change of 2 mA takes place in the collector current. The input resistance and AC current gain are, 1 kΩ & 100, 2 kΩ & 100, 2 kΩ & 1000, 1 kΩ & 200

MARKS App · Accepted Answer

Given: ΔI b = 20 μ A ΔI c = 2 mA ΔV BE = 0 . 04 V Input resistance R input = V BE ΔI b = 0 . 04 20 × 10 - 6 = 2 kΩ A . C . current gain β = ΔI c ΔI b = 2 × 10 - 3 20 × 10 - 6 = 100

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