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Question: Answered & Verified by Expert
A charge is placed at the centre of cube of side $a$ then flux linked with one of its given faces will be
PhysicsElectrostaticsAIIMSAIIMS 2001
Options:
  • A $\frac{Q}{\varepsilon_0}$
  • B $\frac{Q}{6 \varepsilon_0}$
  • C $\frac{Q}{\varepsilon_0 a^2}$
  • D $\frac{Q}{4 \pi \varepsilon_0 a^2}$.
Solution:
2350 Upvotes Verified Answer
The correct answer is: $\frac{Q}{6 \varepsilon_0}$
Gauss's law tells that the total flux through an area enclosing a charge $Q$ is $\frac{Q}{\varepsilon_0}$. Now as the cube is having six faces and as we can assume a symmetrical distribution of fluxes among its faces, the flux associated with one of its faces is $\frac{Q}{6 \varepsilon_0}$.

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