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A charge moves with velocity ' $\mathrm{V}$ ' through electric field (E) as well as magnetic field (B). then the force acting on it is
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The correct answer is:
$q \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$
Force due to electric field $\overrightarrow{\mathrm{F}}_{\mathrm{e}}=\mathrm{q} \overrightarrow{\mathrm{E}}$
Force due to magnetic field $\overrightarrow{\mathrm{F}}_{\mathrm{m}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})$
$\therefore$ Total force $\overrightarrow{\mathrm{F}}=\mathrm{q} \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$
Force due to magnetic field $\overrightarrow{\mathrm{F}}_{\mathrm{m}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})$
$\therefore$ Total force $\overrightarrow{\mathrm{F}}=\mathrm{q} \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$
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