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A charge 'Q' $\mu$ C is placed at the centre of a cube. The flux through one face and two
opposite faces of the cube is respectively
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opposite faces of the cube is respectively
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Verified Answer
The correct answer is:
$\frac{\mathrm{Q}}{6 \epsilon_{0}} \mu \mathrm{Vm}, \quad \frac{\mathrm{Q}}{3 \epsilon_{0}} \mu \mathrm{Vm}$
By using Gauss's Law.
It is given as
$\Phi=\oint \vec{E} \cdot d \vec{s}=\frac{q}{\epsilon_{0}}$
Now, the flux passing through all the six surfaces would be
$\Phi=6 \phi=\frac{q}{\epsilon_{0}}$
And the flux passing through each surface would be
$\phi=\frac{q}{6 \in_{0}}$
It is given as
$\Phi=\oint \vec{E} \cdot d \vec{s}=\frac{q}{\epsilon_{0}}$
Now, the flux passing through all the six surfaces would be
$\Phi=6 \phi=\frac{q}{\epsilon_{0}}$
And the flux passing through each surface would be
$\phi=\frac{q}{6 \in_{0}}$
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