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A charge $q$ is placed at the center of one of the surface of a cube. The flux linked with the cube is:
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Verified Answer
The correct answer is:
$\frac{q}{2 \epsilon_0}$
From 
$\begin{aligned} & 2 \phi=\frac{\mathrm{q}}{\epsilon_0} \\ & \phi=\frac{\mathrm{q}}{2 \epsilon_0}\end{aligned}$
$\begin{aligned} & 2 \phi=\frac{\mathrm{q}}{\epsilon_0} \\ & \phi=\frac{\mathrm{q}}{2 \epsilon_0}\end{aligned}$
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