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A charge $q$ is placed at the centre of a cube. The electric flux passing through the cube is
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Verified Answer
The correct answer is:
$\frac{q}{\varepsilon_{0}}$
According to Gauss's law, total electric flux passing through the cube,
$\phi=\frac{\text { total enclosed charge }}{\varepsilon_{0}}=\frac{q}{\varepsilon_{0}}$
$\phi=\frac{\text { total enclosed charge }}{\varepsilon_{0}}=\frac{q}{\varepsilon_{0}}$
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