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A charge $q$ is placed at the centre of a cube. Then the flux passing through one face of cube will be
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The correct answer is:
$\frac{q}{6 \varepsilon_0}$
Net flux through the cube $\phi_{\text {net }}=\frac{Q}{\varepsilon_0}$; so flux through one face $\phi_{\text {faxe }}=\frac{q}{6 \varepsilon_0}$
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